The size of a dog mostly depends on its breed. Of course, many other factors can affect its size, such as living conditions and diseases. We know that the American Foxhound is a large breed, so generally their size cannot be too small unless there is a congenital deformity. So let's understand how big an American Foxhound can grow.

       When adult, American Foxhound males are about 53-60.9 cm tall, females are 55.8-63.5 cm tall, and they weigh about 30 to 34 kilograms. They are considered a relatively large breed. However, many factors can affect their size. If the dog's genes mutate, it is also possible for the dog to be abnormally large or small.

       Diet is another key factor affecting their size. If an American Foxhound has long-term malnutrition, its bone development may be inadequate, which might cause it to be smaller. On the other hand, an American Foxhound regularly fed large amounts of meat and rich food may become larger or overweight due to overnutrition. Therefore, to maintain a dog's standard size, a proper feeding plan should be established.

       Thus, breed is not the only factor determining the size of a dog. Many circumstances in life can affect them. For example, a dog that has had parvovirus may have impaired digestive absorption, which might cause the dog to be smaller in size. Therefore, a dog's breed, diet, and health condition are all factors that influence its size.